Can someone help me with this statistics problem? Please…?

An insurance sales rep selectes 3 policies to review. The group of policies she can select from contains 8 life policies, 5 automobile policies, and 2 homeowner policies. Find the probability of selecting:
a. Both homeowner policies (I got 3/455 or about .007) (3C2/15C3)

of ways of choosing both homeowner’s = 2C2
# of ways of choosing an additional policy = 13C1
# of ways of choosing three policies from total = 15C3

Prob choosing both = (2C2*13C1)/15C3

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